bias = 2^(k-1) - 1
V = 2^E * M
A.
7.0 = 0b111.000…
M = 0b1.11, f = 0b0.11, E = 2, e = bias + E, V = 7.0
bits
0 10....01 110....
B.
Assume bias » n
bigest odd number, M must be 0b1.111111…., f = 0b0.11111111…(n bits 1)
E = n, V = 0b11111111…(n+1 bits 1) = 2^(n+1) - 1
bits
0 bias+n 11111....
C.
least standard number
M must be 0b1.00…., f = 0b0.000…., E = 1 - bias
V = 2^(1-bias)
reciprocal
V = 2^(bias-1)
M = 0b1.0000…, f = 0b0.000…., E = bias-1, e = bias + E
bits
0 11...101 00000.....